20=-(6-5k)+2(k-1)

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Solution for 20=-(6-5k)+2(k-1) equation: 



20=-(6-5k)+2(k-1)

We move all terms to the left:

20-(-(6-5k)+2(k-1))=0

We add all the numbers together, and all the variables

-(-(-5k+6)+2(k-1))+20=0



We calculate terms in parentheses: -(-(-5k+6)+2(k-1)), so:

-(-5k+6)+2(k-1)

We multiply parentheses

-(-5k+6)+2k-2

We get rid of parentheses

5k+2k-6-2

We add all the numbers together, and all the variables

7k-8

Back to the equation:

-(7k-8)



We get rid of parentheses

-7k+8+20=0

We add all the numbers together, and all the variables

-7k+28=0

We move all terms containing k to the left, all other terms to the right

-7k=-28

k=-28/-7

k=+4

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