20=(40+3)/(x-1)

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Solution for 20=(40+3)/(x-1) equation:



20=(40+3)/(x-1)
We move all terms to the left:
20-((40+3)/(x-1))=0
Domain of the equation: (x-1))!=0
x∈R
We add all the numbers together, and all the variables
-(43/(x-1))+20=0
We multiply all the terms by the denominator
-(43+20*(x-1))=0
We calculate terms in parentheses: -(43+20*(x-1)), so:
43+20*(x-1)
determiningTheFunctionDomain 20*(x-1)+43
We multiply parentheses
20x-20+43
We add all the numbers together, and all the variables
20x+23
Back to the equation:
-(20x+23)
We get rid of parentheses
-20x-23=0
We move all terms containing x to the left, all other terms to the right
-20x=23
x=23/-20
x=-1+3/20

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