20=(3/x)+2

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Solution for 20=(3/x)+2 equation: 



20=(3/x)+2

We move all terms to the left:

20-((3/x)+2)=0



Domain of the equation: x)+2)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+3/x)+2)+20=0

We multiply all the terms by the denominator


-((+3+20*x)+2)=0



We calculate terms in parentheses: -((+3+20*x)+2), so:

(+3+20*x)+2

We add all the numbers together, and all the variables

(20x+3)+2

We get rid of parentheses

20x+3+2

We add all the numbers together, and all the variables

20x+5

Back to the equation:

-(20x+5)



We get rid of parentheses

-20x-5=0

We move all terms containing x to the left, all other terms to the right

-20x=5

x=5/-20

x=-1/4

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