200=x(3x+1)/2

Solution for 200=x(3x+1)/2 equation:

200=x(3x+1)/2

We move all terms to the left:

200-(x(3x+1)/2)=0

We multiply all the terms by the denominator


-(x(3x+1)+200*2)=0


We calculate terms in parentheses: -(x(3x+1)+200*2), so:

x(3x+1)+200*2

We add all the numbers together, and all the variables

x(3x+1)+400

We multiply parentheses

3x^2+x+400

Back to the equation:

-(3x^2+x+400)


We get rid of parentheses

-3x^2-x-400=0

We add all the numbers together, and all the variables

-3x^2-1x-400=0

a = -3; b = -1; c = -400;
Δ = b2-4ac
Δ = -12-4·(-3)·(-400)
Δ = -4799
Delta is less than zero, so there is no solution for the equation