200(340-x)=140(340+x)

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Solution for 200(340-x)=140(340+x) equation: 



200(340-x)=140(340+x)

We move all terms to the left:

200(340-x)-(140(340+x))=0

We add all the numbers together, and all the variables

200(-1x+340)-(140(x+340))=0

We multiply parentheses

-200x-(140(x+340))+68000=0



We calculate terms in parentheses: -(140(x+340)), so:

140(x+340)

We multiply parentheses

140x+47600

Back to the equation:

-(140x+47600)



We get rid of parentheses

-200x-140x-47600+68000=0

We add all the numbers together, and all the variables

-340x+20400=0

We move all terms containing x to the left, all other terms to the right

-340x=-20400

x=-20400/-340

x=+60

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