200(1/200)y=5

Solution for 200(1/200)y=5 equation:

200(1/200)y=5

We move all terms to the left:

200(1/200)y-(5)=0


Domain of the equation: 200)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

200(+1/200)y-5=0

We multiply parentheses

200y^2-5=0

a = 200; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·200·(-5)
Δ = 4000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4000}=\sqrt{400*10}=\sqrt{400}*\sqrt{10}=20\sqrt{10}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{10}}{2*200}=\frac{0-20\sqrt{10}}{400}
=-\frac{20\sqrt{10}}{400}
=-\frac{\sqrt{10}}{20}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{10}}{2*200}=\frac{0+20\sqrt{10}}{400}
=\frac{20\sqrt{10}}{400}
=\frac{\sqrt{10}}{20}
$