20/x-5/2x

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Solution for 20/x-5/2x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

20/x-((5/2)*x) = 0

(-5/2)*x+20/x = 0

20*x^-1-5/2*x^1 = 0

(20*x^0-5/2*x^2)/(x^1) = 0 // * x^2

x^1*(20*x^0-5/2*x^2) = 0

x^1

(-5/2)*x^2+20 = 0

(-5/2)*x^2+20 = 0

DELTA = 0^2-(4*20*(-5/2))

DELTA = 200

DELTA > 0

x = (200^(1/2)+0)/(2*(-5/2)) or x = (0-200^(1/2))/(2*(-5/2))

x = -2*2^(1/2) or x = 2*2^(1/2)

x in { -2*2^(1/2), 2*2^(1/2)} 

x in { -2*2^(1/2), 2*2^(1/2) }

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