20/40-x=10/x

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Solution for 20/40-x=10/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

20/40-x = 10/x // - 10/x

20/40-x-(10/x) = 0

20/40-x-10*x^-1 = 0

1/2*x^0-1*x^1-10*x^-1 = 0

(1/2*x^1-1*x^2-10*x^0)/(x^1) = 0 // * x^2

x^1*(1/2*x^1-1*x^2-10*x^0) = 0

x^1

(1/2)*x-x^2-10 = 0

(1/2)*x-x^2-10 = 0

DELTA = (1/2)^2-(-10*(-1)*4)

DELTA = -159/4

DELTA < 0

x in { } 

x belongs to the empty set

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