20/3x-7=20/x-1

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Solution for 20/3x-7=20/x-1 equation:



20/3x-7=20/x-1
We move all terms to the left:
20/3x-7-(20/x-1)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: x-1)!=0
x∈R
We get rid of parentheses
20/3x-20/x+1-7=0
We calculate fractions
20x/3x^2+(-60x)/3x^2+1-7=0
We add all the numbers together, and all the variables
20x/3x^2+(-60x)/3x^2-6=0
We multiply all the terms by the denominator
20x+(-60x)-6*3x^2=0
Wy multiply elements
-18x^2+20x+(-60x)=0
We get rid of parentheses
-18x^2+20x-60x=0
We add all the numbers together, and all the variables
-18x^2-40x=0
a = -18; b = -40; c = 0;
Δ = b2-4ac
Δ = -402-4·(-18)·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-40}{2*-18}=\frac{0}{-36} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+40}{2*-18}=\frac{80}{-36} =-2+2/9 $

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