20/2x-10+1/x-5=11/2

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Solution for 20/2x-10+1/x-5=11/2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(20/2)*x+1/x-10-5 = 11/2 // - 11/2

(20/2)*x+1/x-(11/2)-10-5 = 0

(20/2)*x+1/x-11/2-10-5 = 0

10*x^1+1*x^-1-41/2*x^0 = 0

(10*x^2-41/2*x^1+1*x^0)/(x^1) = 0 // * x^2

x^1*(10*x^2-41/2*x^1+1*x^0) = 0

x^1

10*x^2+(-41/2)*x+1 = 0

10*x^2+(-41/2)*x+1 = 0

DELTA = (-41/2)^2-(1*4*10)

DELTA = 1521/4

DELTA > 0

x = ((1521/4)^(1/2)-(-41/2))/(2*10) or x = (-(-41/2)-(1521/4)^(1/2))/(2*10)

x = 2 or x = 1/20

x in { 1/20, 2} 

x in { 1/20, 2 }

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