20/15=(6x-7)/51

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Solution for 20/15=(6x-7)/51 equation: 



20/15=(6x-7)/51

We move all terms to the left:

20/15-((6x-7)/51)=0

We calculate fractions


(-((6x-7)*15)/()+()/()=0



We calculate terms in parentheses: +(-((6x-7)*15)/()+()/(), so:

-((6x-7)*15)/()+()/(

We add all the numbers together, and all the variables

-((6x-7)*15)/()+1

We multiply all the terms by the denominator


-((6x-7)*15)+1*()



We calculate terms in parentheses: -((6x-7)*15), so:

(6x-7)*15

We multiply parentheses

90x-105

Back to the equation:

-(90x-105)



We add all the numbers together, and all the variables

-(90x-105)

We get rid of parentheses

-90x+105

Back to the equation:

+(-90x+105)



We get rid of parentheses

-90x+105=0

We move all terms containing x to the left, all other terms to the right

-90x=-105

x=-105/-90

x=1+1/6

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