20/(3x2-4)

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Solution for 20/(3x2-4) equation: 


D( x )

3*x^2-4 = 0

3*x^2-4 = 0

3*x^2-4 = 0

3*x^2 = 4 // : 3

x^2 = 4/3

x^2 = 4/3 // ^ 1/2

abs(x) = (4/3)^(1/2)

x = (4/3)^(1/2) or x = -(4/3)^(1/2)

x in (-oo:-(4/3)^(1/2)) U (-(4/3)^(1/2):(4/3)^(1/2)) U ((4/3)^(1/2):+oo)

20/(3*x^2-4) = 0

x belongs to the empty set

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