20-y/2=4y+11

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Solution for 20-y/2=4y+11 equation: 



20-y/2=4y+11

We move all terms to the left:

20-y/2-(4y+11)=0

We get rid of parentheses

-y/2-4y-11+20=0

We multiply all the terms by the denominator


-y-4y*2-11*2+20*2=0

We add all the numbers together, and all the variables

-1y-4y*2+18=0

Wy multiply elements

-1y-8y+18=0

We add all the numbers together, and all the variables

-9y+18=0

We move all terms containing y to the left, all other terms to the right

-9y=-18

y=-18/-9

y=+2

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