20-3x=-4(4x2)-4(-5-3x)

Solution for 20-3x=-4(4x2)-4(-5-3x) equation:

20-3x=-4(4x^2)-4(-5-3x)

We move all terms to the left:

20-3x-(-4(4x^2)-4(-5-3x))=0

determiningTheFunctionDomain
-(-44x^2-4(-5-3x))-3x+20=0

We add all the numbers together, and all the variables

-(-44x^2-4(-3x-5))-3x+20=0


We calculate terms in parentheses: -(-44x^2-4(-3x-5)), so:

-44x^2-4(-3x-5)

We multiply parentheses

-44x^2+12x+20

Back to the equation:

-(-44x^2+12x+20)


We get rid of parentheses

44x^2-12x-3x-20+20=0

We add all the numbers together, and all the variables

44x^2-15x=0

a = 44; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·44·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*44}=\frac{0}{88}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*44}=\frac{30}{88}
=15/44
$