20-3c+19=3(3c+13)

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Solution for 20-3c+19=3(3c+13) equation:


Simplifying
20 + -3c + 19 = 3(3c + 13)

Reorder the terms:
20 + 19 + -3c = 3(3c + 13)

Combine like terms: 20 + 19 = 39
39 + -3c = 3(3c + 13)

Reorder the terms:
39 + -3c = 3(13 + 3c)
39 + -3c = (13 * 3 + 3c * 3)
39 + -3c = (39 + 9c)

Add '-39' to each side of the equation.
39 + -39 + -3c = 39 + -39 + 9c

Combine like terms: 39 + -39 = 0
0 + -3c = 39 + -39 + 9c
-3c = 39 + -39 + 9c

Combine like terms: 39 + -39 = 0
-3c = 0 + 9c
-3c = 9c

Solving
-3c = 9c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-9c' to each side of the equation.
-3c + -9c = 9c + -9c

Combine like terms: -3c + -9c = -12c
-12c = 9c + -9c

Combine like terms: 9c + -9c = 0
-12c = 0

Divide each side by '-12'.
c = 0

Simplifying
c = 0

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