20-2(x+4)=19(x+5)-56

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Solution for 20-2(x+4)=19(x+5)-56 equation: 



20-2(x+4)=19(x+5)-56

We move all terms to the left:

20-2(x+4)-(19(x+5)-56)=0

We multiply parentheses

-2x-(19(x+5)-56)-8+20=0



We calculate terms in parentheses: -(19(x+5)-56), so:

19(x+5)-56

We multiply parentheses

19x+95-56

We add all the numbers together, and all the variables

19x+39

Back to the equation:

-(19x+39)



We add all the numbers together, and all the variables

-2x-(19x+39)+12=0

We get rid of parentheses

-2x-19x-39+12=0

We add all the numbers together, and all the variables

-21x-27=0

We move all terms containing x to the left, all other terms to the right

-21x=27

x=27/-21

x=-1+2/7

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