20-2(x+3)=10x

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Solution for 20-2(x+3)=10x equation: 



20-2(x+3)=10x

We move all terms to the left:

20-2(x+3)-(10x)=0

We add all the numbers together, and all the variables

-10x-2(x+3)+20=0

We multiply parentheses

-10x-2x-6+20=0

We add all the numbers together, and all the variables

-12x+14=0

We move all terms containing x to the left, all other terms to the right

-12x=-14

x=-14/-12

x=1+1/6

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