20-(x+4)=9x-4(x+5)

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Solution for 20-(x+4)=9x-4(x+5) equation: 



20-(x+4)=9x-4(x+5)

We move all terms to the left:

20-(x+4)-(9x-4(x+5))=0

We get rid of parentheses

-x-(9x-4(x+5))-4+20=0



We calculate terms in parentheses: -(9x-4(x+5)), so:

9x-4(x+5)

We multiply parentheses

9x-4x-20

We add all the numbers together, and all the variables

5x-20

Back to the equation:

-(5x-20)



We add all the numbers together, and all the variables

-1x-(5x-20)+16=0

We get rid of parentheses

-1x-5x+20+16=0

We add all the numbers together, and all the variables

-6x+36=0

We move all terms containing x to the left, all other terms to the right

-6x=-36

x=-36/-6

x=+6

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