20-(7x-3)=65

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Solution for 20-(7x-3)=65 equation:



20-(7x-3)=65
We move all terms to the left:
20-(7x-3)-(65)=0
We add all the numbers together, and all the variables
-(7x-3)-45=0
We get rid of parentheses
-7x+3-45=0
We add all the numbers together, and all the variables
-7x-42=0
We move all terms containing x to the left, all other terms to the right
-7x=42
x=42/-7
x=-6

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