20-(3b-9+1)=10

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Solution for 20-(3b-9+1)=10 equation: 



20-(3b-9+1)=10

We move all terms to the left:

20-(3b-9+1)-(10)=0

We add all the numbers together, and all the variables

-(3b-8)+20-10=0

We add all the numbers together, and all the variables

-(3b-8)+10=0

We get rid of parentheses

-3b+8+10=0

We add all the numbers together, and all the variables

-3b+18=0

We move all terms containing b to the left, all other terms to the right

-3b=-18

b=-18/-3

b=+6

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