20-(2y-6)=10

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Solution for 20-(2y-6)=10 equation: 



20-(2y-6)=10

We move all terms to the left:

20-(2y-6)-(10)=0

We add all the numbers together, and all the variables

-(2y-6)+10=0

We get rid of parentheses

-2y+6+10=0

We add all the numbers together, and all the variables

-2y+16=0

We move all terms containing y to the left, all other terms to the right

-2y=-16

y=-16/-2

y=+8

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