20+k=-3+2(3k-1)

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Solution for 20+k=-3+2(3k-1) equation: 



20+k=-3+2(3k-1)

We move all terms to the left:

20+k-(-3+2(3k-1))=0



We calculate terms in parentheses: -(-3+2(3k-1)), so:

-3+2(3k-1)

determiningTheFunctionDomain
2(3k-1)-3

We multiply parentheses

6k-2-3

We add all the numbers together, and all the variables

6k-5

Back to the equation:

-(6k-5)



We get rid of parentheses

k-6k+5+20=0

We add all the numbers together, and all the variables

-5k+25=0

We move all terms containing k to the left, all other terms to the right

-5k=-25

k=-25/-5

k=+5

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