20+4/5y=13

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Solution for 20+4/5y=13 equation: 



20+4/5y=13

We move all terms to the left:

20+4/5y-(13)=0



Domain of the equation: 5y!=0

y!=0/5

y!=0

y∈R



We add all the numbers together, and all the variables

4/5y+7=0

We multiply all the terms by the denominator


7*5y+4=0

Wy multiply elements

35y+4=0

We move all terms containing y to the left, all other terms to the right

35y=-4

y=-4/35

y=-4/35

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