20+3y=10y-4y

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Solution for 20+3y=10y-4y equation: 



20+3y=10y-4y

We move all terms to the left:

20+3y-(10y-4y)=0

We add all the numbers together, and all the variables

3y-(+6y)+20=0

We get rid of parentheses

3y-6y+20=0

We add all the numbers together, and all the variables

-3y+20=0

We move all terms containing y to the left, all other terms to the right

-3y=-20

y=-20/-3

y=6+2/3

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