20+3x+6=4x+12

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Solution for 20+3x+6=4x+12 equation: 



20+3x+6=4x+12

We move all terms to the left:

20+3x+6-(4x+12)=0

We add all the numbers together, and all the variables

3x-(4x+12)+26=0

We get rid of parentheses

3x-4x-12+26=0

We add all the numbers together, and all the variables

-1x+14=0

We move all terms containing x to the left, all other terms to the right

-x=-14

x=-14/-1

x=+14

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