20+(0.50m)=30+(0.25m)

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Solution for 20+(0.50m)=30+(0.25m) equation: 



20+(0.50m)=30+(0.25m)

We move all terms to the left:

20+(0.50m)-(30+(0.25m))=0

We add all the numbers together, and all the variables

(+0.50m)-(30+(+0.25m))+20=0

We get rid of parentheses

0.50m-(30+(+0.25m))+20=0



We calculate terms in parentheses: -(30+(+0.25m)), so:

30+(+0.25m)

determiningTheFunctionDomain
(+0.25m)+30

We get rid of parentheses

0.25m+30

Back to the equation:

-(0.25m+30)



We get rid of parentheses

0.50m-0.25m-30+20=0

We add all the numbers together, and all the variables

0.25m-10=0

We move all terms containing m to the left, all other terms to the right

0.25m=10

m=10/0.25

m=40

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