20*2=12*2+(5+x)*2

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Solution for 20*2=12*2+(5+x)*2 equation:



20*2=12*2+(5+x)*2
We move all terms to the left:
20*2-(12*2+(5+x)*2)=0
We add all the numbers together, and all the variables
-(12*2+(x+5)*2)+20*2=0
We add all the numbers together, and all the variables
-(12*2+(x+5)*2)+40=0
We calculate terms in parentheses: -(12*2+(x+5)*2), so:
12*2+(x+5)*2
determiningTheFunctionDomain (x+5)*2+12*2
We add all the numbers together, and all the variables
(x+5)*2+24
We multiply parentheses
2x+10+24
We add all the numbers together, and all the variables
2x+34
Back to the equation:
-(2x+34)
We get rid of parentheses
-2x-34+40=0
We add all the numbers together, and all the variables
-2x+6=0
We move all terms containing x to the left, all other terms to the right
-2x=-6
x=-6/-2
x=+3

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