20(y/5)-7=4y+3

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Solution for 20(y/5)-7=4y+3 equation: 



20(y/5)-7=4y+3

We move all terms to the left:

20(y/5)-7-(4y+3)=0

We add all the numbers together, and all the variables

20(+y/5)-(4y+3)-7=0

We multiply parentheses

20y-(4y+3)-7=0

We get rid of parentheses

20y-4y-3-7=0

We add all the numbers together, and all the variables

16y-10=0

We move all terms containing y to the left, all other terms to the right

16y=10

y=10/16

y=5/8

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