20(y+2)=5(3y+4)

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Solution for 20(y+2)=5(3y+4) equation:


Simplifying
20(y + 2) = 5(3y + 4)

Reorder the terms:
20(2 + y) = 5(3y + 4)
(2 * 20 + y * 20) = 5(3y + 4)
(40 + 20y) = 5(3y + 4)

Reorder the terms:
40 + 20y = 5(4 + 3y)
40 + 20y = (4 * 5 + 3y * 5)
40 + 20y = (20 + 15y)

Solving
40 + 20y = 20 + 15y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-15y' to each side of the equation.
40 + 20y + -15y = 20 + 15y + -15y

Combine like terms: 20y + -15y = 5y
40 + 5y = 20 + 15y + -15y

Combine like terms: 15y + -15y = 0
40 + 5y = 20 + 0
40 + 5y = 20

Add '-40' to each side of the equation.
40 + -40 + 5y = 20 + -40

Combine like terms: 40 + -40 = 0
0 + 5y = 20 + -40
5y = 20 + -40

Combine like terms: 20 + -40 = -20
5y = -20

Divide each side by '5'.
y = -4

Simplifying
y = -4

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