20(x-5)=-10(x+3)

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Solution for 20(x-5)=-10(x+3) equation: 



20(x-5)=-10(x+3)

We move all terms to the left:

20(x-5)-(-10(x+3))=0

We multiply parentheses

20x-(-10(x+3))-100=0



We calculate terms in parentheses: -(-10(x+3)), so:

-10(x+3)

We multiply parentheses

-10x-30

Back to the equation:

-(-10x-30)



We get rid of parentheses

20x+10x+30-100=0

We add all the numbers together, and all the variables

30x-70=0

We move all terms containing x to the left, all other terms to the right

30x=70

x=70/30

x=2+1/3

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