20(x+2)=4(5x+10)+31

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Solution for 20(x+2)=4(5x+10)+31 equation: 



20(x+2)=4(5x+10)+31

We move all terms to the left:

20(x+2)-(4(5x+10)+31)=0

We multiply parentheses

20x-(4(5x+10)+31)+40=0



We calculate terms in parentheses: -(4(5x+10)+31), so:

4(5x+10)+31

We multiply parentheses

20x+40+31

We add all the numbers together, and all the variables

20x+71

Back to the equation:

-(20x+71)



We get rid of parentheses

20x-20x-71+40=0

We add all the numbers together, and all the variables

-31!=0

There is no solution for this equation

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