20(v+3)-4v=4(4v+2)-12

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Solution for 20(v+3)-4v=4(4v+2)-12 equation: 


Simplifying
20(v + 3) + -4v = 4(4v + 2) + -12

Reorder the terms:
20(3 + v) + -4v = 4(4v + 2) + -12
(3 * 20 + v * 20) + -4v = 4(4v + 2) + -12
(60 + 20v) + -4v = 4(4v + 2) + -12

Combine like terms: 20v + -4v = 16v
60 + 16v = 4(4v + 2) + -12

Reorder the terms:
60 + 16v = 4(2 + 4v) + -12
60 + 16v = (2 * 4 + 4v * 4) + -12
60 + 16v = (8 + 16v) + -12

Reorder the terms:
60 + 16v = 8 + -12 + 16v

Combine like terms: 8 + -12 = -4
60 + 16v = -4 + 16v

Add '-16v' to each side of the equation.
60 + 16v + -16v = -4 + 16v + -16v

Combine like terms: 16v + -16v = 0
60 + 0 = -4 + 16v + -16v
60 = -4 + 16v + -16v

Combine like terms: 16v + -16v = 0
60 = -4 + 0
60 = -4

Solving
60 = -4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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