20(50+12,500f)=14,040f

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Solution for 20(50+12,500f)=14,040f equation: 



20(50+12.500f)=14.040f

We move all terms to the left:

20(50+12.500f)-(14.040f)=0

We add all the numbers together, and all the variables

20(12.500f+50)-(+14.040f)=0

We multiply parentheses

240f-(+14.040f)+1000=0

We get rid of parentheses

240f-14.040f+1000=0

We add all the numbers together, and all the variables

225.96f+1000=0

We move all terms containing f to the left, all other terms to the right

225.96f=-1000

f=-1000/225.96

f=-4+30.430379746836/71.506329113925

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