20(4x+7)=-30(x-5)

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Solution for 20(4x+7)=-30(x-5) equation: 



20(4x+7)=-30(x-5)

We move all terms to the left:

20(4x+7)-(-30(x-5))=0

We multiply parentheses

80x-(-30(x-5))+140=0



We calculate terms in parentheses: -(-30(x-5)), so:

-30(x-5)

We multiply parentheses

-30x+150

Back to the equation:

-(-30x+150)



We get rid of parentheses

80x+30x-150+140=0

We add all the numbers together, and all the variables

110x-10=0

We move all terms containing x to the left, all other terms to the right

110x=10

x=10/110

x=1/11

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