20(3x-2)=12(x+1)

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Solution for 20(3x-2)=12(x+1) equation:



20(3x-2)=12(x+1)
We move all terms to the left:
20(3x-2)-(12(x+1))=0
We multiply parentheses
60x-(12(x+1))-40=0
We calculate terms in parentheses: -(12(x+1)), so:
12(x+1)
We multiply parentheses
12x+12
Back to the equation:
-(12x+12)
We get rid of parentheses
60x-12x-12-40=0
We add all the numbers together, and all the variables
48x-52=0
We move all terms containing x to the left, all other terms to the right
48x=52
x=52/48
x=1+1/12

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