20(3/4x)+20(-2/5x)+20(7)=20(7/10x)

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Solution for 20(3/4x)+20(-2/5x)+20(7)=20(7/10x) equation: 



20(3/4x)+20(-2/5x)+20(7)=20(7/10x)

We move all terms to the left:

20(3/4x)+20(-2/5x)+20(7)-(20(7/10x))=0



Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 10x))!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

20(+3/4x)+20(-2/5x)-(20(+7/10x))+207=0

We multiply parentheses

60x-40x-(20(+7/10x))+207=0

We multiply all the terms by the denominator


60x*10x))-40x*10x))-(20(+7+207*10x))=0

We add all the numbers together, and all the variables

60x*10x))-40x*10x))-(20(207*10x+7))=0

Wy multiply elements

60000x^4=0

We do not support expression: x^4

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