20(3-m)+14m=12

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Solution for 20(3-m)+14m=12 equation: 



20(3-m)+14m=12

We move all terms to the left:

20(3-m)+14m-(12)=0

We add all the numbers together, and all the variables

20(-1m+3)+14m-12=0

We add all the numbers together, and all the variables

14m+20(-1m+3)-12=0

We multiply parentheses

14m-20m+60-12=0

We add all the numbers together, and all the variables

-6m+48=0

We move all terms containing m to the left, all other terms to the right

-6m=-48

m=-48/-6

m=+8

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