20(2x-8)=4(3x-5)

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Solution for 20(2x-8)=4(3x-5) equation:


Simplifying
20(2x + -8) = 4(3x + -5)

Reorder the terms:
20(-8 + 2x) = 4(3x + -5)
(-8 * 20 + 2x * 20) = 4(3x + -5)
(-160 + 40x) = 4(3x + -5)

Reorder the terms:
-160 + 40x = 4(-5 + 3x)
-160 + 40x = (-5 * 4 + 3x * 4)
-160 + 40x = (-20 + 12x)

Solving
-160 + 40x = -20 + 12x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-12x' to each side of the equation.
-160 + 40x + -12x = -20 + 12x + -12x

Combine like terms: 40x + -12x = 28x
-160 + 28x = -20 + 12x + -12x

Combine like terms: 12x + -12x = 0
-160 + 28x = -20 + 0
-160 + 28x = -20

Add '160' to each side of the equation.
-160 + 160 + 28x = -20 + 160

Combine like terms: -160 + 160 = 0
0 + 28x = -20 + 160
28x = -20 + 160

Combine like terms: -20 + 160 = 140
28x = 140

Divide each side by '28'.
x = 5

Simplifying
x = 5

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