20(2x+3)=600

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Solution for 20(2x+3)=600 equation: 



20(2x+3)=600

We move all terms to the left:

20(2x+3)-(600)=0

We multiply parentheses

40x+60-600=0

We add all the numbers together, and all the variables

40x-540=0

We move all terms containing x to the left, all other terms to the right

40x=540

x=540/40

x=13+1/2

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