20(27+1)+15(9+1)-35(3x+1)=

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Solution for 20(27+1)+15(9+1)-35(3x+1)= equation:


Simplifying
20(27 + 1) + 15(9 + 1) + -35(3x + 1) = 0

Combine like terms: 27 + 1 = 28
20(28) + 15(9 + 1) + -35(3x + 1) = 0

Multiply 20 * 28
560 + 15(9 + 1) + -35(3x + 1) = 0

Combine like terms: 9 + 1 = 10
560 + 15(10) + -35(3x + 1) = 0

Multiply 15 * 10
560 + 150 + -35(3x + 1) = 0

Reorder the terms:
560 + 150 + -35(1 + 3x) = 0
560 + 150 + (1 * -35 + 3x * -35) = 0
560 + 150 + (-35 + -105x) = 0

Combine like terms: 560 + 150 = 710
710 + -35 + -105x = 0

Combine like terms: 710 + -35 = 675
675 + -105x = 0

Solving
675 + -105x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-675' to each side of the equation.
675 + -675 + -105x = 0 + -675

Combine like terms: 675 + -675 = 0
0 + -105x = 0 + -675
-105x = 0 + -675

Combine like terms: 0 + -675 = -675
-105x = -675

Divide each side by '-105'.
x = 6.428571429

Simplifying
x = 6.428571429

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