20(-0.5+0.3y)=2/3(9y-15)

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Solution for 20(-0.5+0.3y)=2/3(9y-15) equation: 



20(-0.5+0.3y)=2/3(9y-15)

We move all terms to the left:

20(-0.5+0.3y)-(2/3(9y-15))=0



Domain of the equation: 3(9y-15))!=0

y∈R



We add all the numbers together, and all the variables

20(0.3y-0.5)-(2/3(9y-15))=0

We multiply parentheses

0y-(2/3(9y-15))-10=0

We multiply all the terms by the denominator


0y*3(9y-15))-(2-10*3(9y-15))=0

Wy multiply elements

0y^2(9-30y(9=0

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