2/y-y/3=5/3

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Solution for 2/y-y/3=5/3 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

2/y-(y/3) = 5/3 // - 5/3

2/y-(y/3)-(5/3) = 0

2/y-(y/3)-5/3 = 0

2*y^-1-1/3*y^1-5/3*y^0 = 0

(2*y^0-1/3*y^2-5/3*y^1)/(y^1) = 0 // * y^2

y^1*(2*y^0-1/3*y^2-5/3*y^1) = 0

y^1

(-1/3)*y^2+(-5/3)*y+2 = 0

(-1/3)*y^2+(-5/3)*y+2 = 0

DELTA = (-5/3)^2-(2*4*(-1/3))

DELTA = 49/9

DELTA > 0

y = ((49/9)^(1/2)-(-5/3))/(2*(-1/3)) or y = (-(-5/3)-(49/9)^(1/2))/(2*(-1/3))

y = -6 or y = 1

y in { -6, 1} 

y in { -6, 1 }

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