2/y-2/y-3=3

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Solution for 2/y-2/y-3=3 equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

2/y-(2/y)-3 = 3 // - 3

2/y-(2/y)-3-3 = 0

2/y-2*y^-1-3-3 = 0

-6 = 0

y belongs to the empty set

y belongs to the empty set

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