2/y+3/5=A/5y

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Solution for 2/y+3/5=A/5y equation: 



2/y+3/5=/5y

We move all terms to the left:

2/y+3/5-(/5y)=0



Domain of the equation: y!=0

y∈R





Domain of the equation: 5y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

2/y-(+/5y)+3/5=0

We get rid of parentheses

2/y-/5y+3/5=0

We calculate fractions


250y/125y^2+(-y)/125y^2+3y/125y^2=0

We add all the numbers together, and all the variables

250y/125y^2+(-1y)/125y^2+3y/125y^2=0

We multiply all the terms by the denominator


250y+(-1y)+3y=0

We add all the numbers together, and all the variables

253y+(-1y)=0

We get rid of parentheses

253y-1y=0

We add all the numbers together, and all the variables

252y=0

y=0/252

y=0

Równanie nie ma rozwiązania

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