2/x=4/(2x)-2

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Solution for 2/x=4/(2x)-2 equation: 



2/x=4/(2x)-2

We move all terms to the left:

2/x-(4/(2x)-2)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: 2x-2)!=0

x∈R



We get rid of parentheses

2/x-4/2x+2=0

We calculate fractions


4x/2x^2+(-4x)/2x^2+2=0

We multiply all the terms by the denominator


4x+(-4x)+2*2x^2=0

Wy multiply elements

4x^2+4x+(-4x)=0

We get rid of parentheses

4x^2+4x-4x=0

We add all the numbers together, and all the variables

4x^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$

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