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2/x-6+3/3x-18=14
We move all terms to the left:
2/x-6+3/3x-18-(14)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
2/x+3/3x-38=0
We calculate fractions
6x/3x^2+3x/3x^2-38=0
We multiply all the terms by the denominator
6x+3x-38*3x^2=0
We add all the numbers together, and all the variables
9x-38*3x^2=0
Wy multiply elements
-114x^2+9x=0
a = -114; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-114)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-114}=\frac{-18}{-228} =3/38 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-114}=\frac{0}{-228} =0 $
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