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2/x-1/(x-1)=1/(x+2)
We move all terms to the left:
2/x-1/(x-1)-(1/(x+2))=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (x-1)!=0
We move all terms containing x to the left, all other terms to the right
x!=1
x∈R
Domain of the equation: (x+2))!=0We calculate fractions
x∈R
(2*(x-1)*(x+2)))/(x*(x-1)*(x+2)))+(-1x^2*()/(x*(x-1)*(x+2)))+(-(x^2*())/(x*(x-1)*(x+2)))=0
We calculate terms in parentheses: +(2*(x-1)*(x+2)))/(x*(x-1)*(x+2)))+(-1x^2*()/(x*(x-1)*(x+2)))+(-(x^2*())/(x*(x-1)*(x+2))), so:
2*(x-1)*(x+2)))/(x*(x-1)*(x+2)))+(-1x^2*()/(x*(x-1)*(x+2)))+(-(x^2*())/(x*(x-1)*(x+2))
determiningTheFunctionDomain 2)))+(-1x^2*()/(x*(x+2*(x-1)*(x+2)))/(x*(x-1)*(x-1)*(x+2)))+(-(x^2*())/(x*(x-1)*(x+2))
We add all the numbers together, and all the variables
2)))+(-1x^2*()/(x*(x+2*(x-1)*(x+2)))/(x*(x-1)*(x-1)*(x+2)))+(-(x^2*())/(x*(x-1)*(x
We multiply all the terms by the denominator
2)))+(-1x^2*()+2*(x-1)*(x+2)))-1*x*(x*(x-1*x*(x*(x+2)))+(-(x^2*())-1*x*(x*(x
Back to the equation:
+(2)))+(-1x^2*()+2*(x-1)*(x+2)))-1*x*(x*(x-1*x*(x*(x+2)))+(-(x^2*())-1*x*(x*(x)
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