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2/x+5/3x=9
We move all terms to the left:
2/x+5/3x-(9)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x!=0We calculate fractions
x!=0/3
x!=0
x∈R
6x/3x^2+5x/3x^2-9=0
We multiply all the terms by the denominator
6x+5x-9*3x^2=0
We add all the numbers together, and all the variables
11x-9*3x^2=0
Wy multiply elements
-27x^2+11x=0
a = -27; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-27)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-27}=\frac{-22}{-54} =11/27 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-27}=\frac{0}{-54} =0 $
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