2/x+3=7/4x

Solution for 2/x+3=7/4x equation:

2/x+3=7/4x

We move all terms to the left:

2/x+3-(7/4x)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2/x-(+7/4x)+3=0

We get rid of parentheses

2/x-7/4x+3=0

We calculate fractions


8x/4x^2+(-7x)/4x^2+3=0

We multiply all the terms by the denominator


8x+(-7x)+3*4x^2=0

Wy multiply elements

12x^2+8x+(-7x)=0

We get rid of parentheses

12x^2+8x-7x=0

We add all the numbers together, and all the variables

12x^2+x=0

a = 12; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·12·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*12}=\frac{-2}{24}
=-1/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*12}=\frac{0}{24}
=0
$