2/x+3/x=1/(x-4

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Solution for 2/x+3/x=1/(x-4 equation: 



2/x+3/x=1/(x-4

We move all terms to the left:

2/x+3/x-(1/(x-4)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x-4)!=0

We move all terms containing x to the left, all other terms to the right

x!=4

x∈R



We calculate fractions


(3x-10)/(x^2-4x)+(-(1*x)/(x^2-4x)=0



We calculate terms in parentheses: +(-(1*x)/(x^2-4x), so:

-(1*x)/(x^2-4x

We add all the numbers together, and all the variables

-(+x)/(x^2-4x

We multiply all the terms by the denominator


-(+x)

We get rid of parentheses

-x

Back to the equation:

+(-x)



We add all the numbers together, and all the variables

(3x-10)/(x^2-4x)+(-1x)=0

We get rid of parentheses

(3x-10)/(x^2-4x)-1x=0

We multiply all the terms by the denominator


(3x-10)-1x*(x^2-4x)=0

We multiply parentheses

-x^3+4x^2+(3x-10)=0

We get rid of parentheses

-x^3+4x^2+3x-10=0

We do not support expression: x^3

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